An electric potential difference will be indu | vedclass

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(D) The motional electromotive force $(EMF)$ induced in a conductor moving in a magnetic field is given by the formula $\varepsilon = (\vec{v} 	imes

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$M$

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(D) The motional electromotive force $(EMF)$ induced in a conductor moving in a magnetic field is given by the formula $\varepsilon = (\vec{v} 	imes \vec{B}) \cdot \vec{l}$.For an induced potential difference to exist,the velocity of the conductor $\vec{v}$,the magnetic field $\vec{B}$,and the length of the conductor $\vec{l}$ must be mutually perpendicular.In the given diagram,the magnetic field $\vec{B}$ is directed from the North $(N)$ pole to the South $(S)$ pole (along the $L-Q$ axis).The length of the conductor is along the axis perpendicular to the page.To induce an $EMF$,the velocity $\vec{v}$ must be perpendicular to both $\vec{B}$ and the length of the conductor.Moving the conductor in direction $M$ (upward) or $P$ (downward) satisfies the condition of being perpendicular to the magnetic field lines ($L-Q$ direction) and the length of the conductor.However,looking at the standard orientation of such problems,direction $M$ is the most appropriate choice to ensure the motional $EMF$ is generated across the ends of the conductor.

An electric potential difference will be induced between the ends of the conductor shown in the diagram when the conductor moves in the direction:

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